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A maths home work quiz

September 4th, 2008 by admin · 18 Comments

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  1. A maths home work quiz
  2. The home work quiz

I give you 3 digits and a result and you must put all the signs necessary to restore the equality.

I’ll give you an example. The remainder you solve by yourself.

2 + 2 + 2 = 6

Easy isn’t this? It’s the same for the remainder.

1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

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18 responses so far ↓

  • 1 Peter Gallagher // Sep 4, 2008 at 9:23 am

    David,

    To avoid spoilers, I’ve sent you an email with some suggested solutions. Neat!

    Best,

    Peter

    Peter Gallaghers last blog post..Chroming the Internet

  • 2 davids // Sep 4, 2008 at 9:50 am

    Cool and well done. Not the only solutions, so I will post all the answers sent in tomorrow. Cheers

  • 3 Jan Pompe // Sep 4, 2008 at 11:07 am

    I’ll wait for the solutions I have one for all except the first and am going to give up on it.

  • 4 Carl // Sep 4, 2008 at 3:08 pm

    I think the solutions to 3,4,5,6,7,8 and 9 are fairly straightforward. However, number 1 isn’t.
    I’ve tried to reproduce it below, the right hand side should read “the infinite root of 6″.

    1 x 1 x 1 = ∞√6

  • 5 Jan Pompe // Sep 4, 2008 at 6:22 pm

    carl

    1*1*1 = 6^0 did cross the mind but I thought it might not be legit.

  • 6 Josh // Sep 5, 2008 at 1:03 am

    φ(n) (Euler’s totient function) is your friend…

  • 7 Bob D // Sep 5, 2008 at 1:14 am

    Are other digits allowed as subscripts or superscripts?

  • 8 Peter Gallagher // Sep 5, 2008 at 1:19 am

    If you’re thinking Euler (or Boltzmanm, Planck or Avagadro for that matter) your friend may really be the Magic Number Machine.

    Peter Gallaghers last blog post..Precautionary principle, misleading and undemocratic

  • 9 Peter Gallagher // Sep 5, 2008 at 1:20 am

    Damn… Try that link again: Magic Number Machine

    Peter Gallaghers last blog post..Precautionary principle, misleading and undemocratic

  • 10 David Stockwell // Sep 5, 2008 at 1:29 am

    Bob D: Yes.
    Jan: 6^0 Works for me

  • 11 Jan Pompe // Sep 5, 2008 at 1:47 am

    Thanks David,

    for both the fun and the answer.

    I wasn’t sure whether we we could operate on both sides.

    Now I’m really curious about what Josh might be thinking. Josh?

  • 12 David Stockwell // Sep 5, 2008 at 2:05 am

    φ(3+3+3) =6
    φ(6+6+6) =6

    But are you ready for my answer?

  • 13 Jan Pompe // Sep 5, 2008 at 2:36 am

    David

    Ahah.

    I am are others?

  • 14 David Stockwell // Sep 5, 2008 at 2:43 am

    OK: Where n is any number:

    (n^0 + n^0 + n^0)! = 6

    I’ll collate all the answers into a post if you want to surrender them now.

    David Stockwells last blog post..A maths home work quiz

  • 15 Josh // Sep 5, 2008 at 11:35 am

    1! × ⌊tan 1⌋ + log 1 = ⌈cos 6⌉

  • 16 Geoff Sherrington // Sep 7, 2008 at 11:03 am

    Good mathematicians start conversations either by drawing a triple integral first, or by explaining “On one hand….”

    Digital solutions:

    On one hand I found 5 fingers + 1 thumb = 6.

    On the other hand, I found 4 fingers + 1 thumb = 5.

    (Noted asymmetry and mirroring).

    While looking for a nice solution in hand, I deduced that people smart enough to know about Euler’s Totient Function are w…….s. (wiki readers).

    Time for solution = 0.3 milliseconds.

    (This has not been peer reviewed).

  • 17 Ian Random // Sep 9, 2008 at 1:14 am

    (1+1+1)!=6

  • 18 Geoff Sherrington // Sep 10, 2008 at 2:32 am

    More serious this time, does this fit the rules of the game? Might not work for n = 0.

    {[(n)! – (n-1)!]/3 + [(n)! – (n-1)!]/3 + [(n)! – (n-1)!]/3 } = n

    I have never really thought about the sign of the factorial of a negative integer. I guess it alternates.

    Thought time: 2 weeks

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