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5
Sep
OK, here are the solutions I received to the home work quiz. Thanks to Alan D. McIntire, Peter Gallagher, Jan Pompe, BobD and Josh for contributions.
1:
(1+1+1)!=6
1*1*1 = 6^0
1 x 1 x 1 = ∞√6
11|4 + 1 = 6 where the 4 is a subscript indicating “base 4″
1×1+1 = φ(6)
2:
(2*2) – 2 = 6
2 + 2 + 2 = 6
3:
(3*3) – 3 = 6
φ(3+3+3) =6
4:
4^(1/2) + 4^(1/2) + 4^(1/2) = 6
4 + 4 – 4^(1/2) = 6
5:
(5/5) + 5 = 6
5 + 5 / 5 = 6
6:
6+6-6=6
6 – 6 + 6 = 6
φ(6+6+6) =6
7:
7 – (7/7) = 6
8:
8-8^0-8^0 = 6
8^(1/3) + 8^(1/3) + 8^(1/3) = 6
8 – (8+8)^.25 = 6
Γ(8 -8/8) = 6!
9:
(9 + 9) / 9^ (1/2) = 6
9^(1/2) x 9^(1/2) – 9^(1/2) = 6
9 – (9 / 9^.5) = 6
φ is Euler’s Totient Function.
Γ is the Gamma function.
And my solution where n is any number:
(n^0 + n^0 + n^0)! = 6
- Published by david stockwell in: All
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